Question

2t square - t - 10 factorize this

Answer 1

Answer:

here,

2t² -t - 10 = 0

=> 2t² -5t +4t -10 = 0

=> t( 2t -5) +2( 2t - 5) = 0

=> (2t -5)( t +2) = 0

=> 2t -5 = 0 ... or , t +2 = 0

=> t = 5/2 or t = -2..

I hope it will help you

$..$

Answer 2

Factors are $\bf \red{2{t}^{2} -t-10 =(2{t} -5)(t+2) }$

Given:

• $2{t}^{2} -t-10$

To find:

• Factors of quadratic polynomial.

Solution:

Concept to be used:

A standard quadratic polynomial is given by $\bf a {x}^{2} + bx + c$ where a≠0.

In factorisation using split the middle term.Split b like that the multiplication of parts equal to ac.

Step 1:

Here,

b= -t

Multiplication of ac= -20t²

So,

-t= 4t-5t

And

(4t)(-5t) = -20t²

Step 2:

Factorise the polynomial.

$2{t}^{2} -t-10= 2{t}^{2} -5t+4t-10$

or

$2{t}^{2} -t-10= t(2{t} -5)+2(2t-5)$

or

$2{t}^{2} -t-10= (2{t} -5)(t+2)$

or

Thus,

Factors are $\bf 2{t}^{2} -t-10 =(2{t} -5)(t+2)$

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