2tan^-1( x) = sin^-1(2x/1+x^2) prove
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hope it helps
###Avinash####
###Avinash####
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hello users........
Here
we have to prove
2tan^-1( x) = sin^-1(2x/1+x^2)
now ,
solution:-
know that
tan^-1(tan x) = x
& (2tan t )/1+ tan²t = sin 2t
now
Taking LHS
= 2tan^-1( x)
put x= tan t
here
2tan^-1(tan t) = 2t
now
solving RHS
sin^-1(2x/1+x^2) = sin^-1 {(2tan t )/1+ tan²t}
=> sin^-1 (sin 2t) = 2t
hence
LHS = RHS
✡✡ hope it helps ✡✡
Here
we have to prove
2tan^-1( x) = sin^-1(2x/1+x^2)
now ,
solution:-
know that
tan^-1(tan x) = x
& (2tan t )/1+ tan²t = sin 2t
now
Taking LHS
= 2tan^-1( x)
put x= tan t
here
2tan^-1(tan t) = 2t
now
solving RHS
sin^-1(2x/1+x^2) = sin^-1 {(2tan t )/1+ tan²t}
=> sin^-1 (sin 2t) = 2t
hence
LHS = RHS
✡✡ hope it helps ✡✡
Ankit1408:
if possible please mark it as a brainlist answer
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