Question

2tan 30 upon 1-tan square 30​

Answer 1

Answer:

hey here is your answer

(2 tan 30)/(1+tan^2 30) = sin 60?

LHS = (2 tan 30)/(1+tan^2 30)

= (2tan30)/ (1+ sin^2 30/ cos^2 30)

= (2tan30)/ (sin^2 30 + Cos^2 30)/ cos ^2 30

= (2tan30) / (1/cos^2 30) [Because sin^2 theta + cos^2 theta =1]

= 2tan30*cos^2 30/1

= (2sin30/cos30) *cos^2 30

= 2sin 30* cos 30 [ because 2(sin theta) * (Cos theta) = sin 2 theta )

= sin 2*30

= sin60 = RHS proved.

Thank you.

hope it help you ☺️

Answer 2

Answer:

(2√3-1) /3

Step-by-step explanation:

2tan(30)-tan^2(30°)

=>(2×(1/√3))-(1/√3)^2

=>(2/√3)-(1/3)

=>(2√3-1)/3.