Question

(2x-1)^2 = 0 solve by factorisation method

Answer 1

Answer:

$(2x - 1)^{2} = (2x)^{2} - 2 (2x) (1) + 1^{2}$ (Identity 2)

= $4x^{2} - 4x + 1 = 4x^{2} - 2x - 2x + 1 = 2x (2x -1) -1 (2x - 1) = (2x - 1) (2x - 1) (verification)$

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