Question

(2x - 1)³
expand the following​

Answer 1

To expand

(2x - 1)³

Use identity

(a-b)³

That is equal to

= a³ - 3a²b + 3ab² - b³

Now here a = 2x

and b = 1

Putting value

(2x - 1)³ = (2x)³ - 3×(2x)²×(1) + 3×(2x)×(1)² - (1)³

= 8x³ - 6x² + 6x - 1

Finally the answer is

8x³ - 6x² + 6x - 1

Answer 2

Step-by-step explanation:

(2x)^3-(1)^3- 3 ×2x ×1(2x-1)

8x3-1-6x(2x-1)

$8x3 - 1 - {12x}^{2} + 6x$

$8x3 - {12x}^{2} + 6x - 1$