Question

(2x-1)/3 =(x-2) / 3 +1​

Answer 1

Given :-

• $\sf \dfrac{2x - 1}{3} = \dfrac{x - 2}{3} \: \: + \: 1$

Need To Find Out :-

• Value of x

Solution :-

$\sf\purple{ \dfrac{2x - 1}{3} = \dfrac{x - 2}{3} \: \: + \: 1}$

$\sf :\implies \dfrac{2x - 1}{3} = \dfrac{ [ \: (x - 2) \times 1 \: ]+ (1 \times 3)}{3}$

$: \implies \: \sf \dfrac{2x - 1}{3} = \dfrac{ (\: x - 2 \: )+ (3)}{3}$

$\sf :\implies \dfrac{2x - 1}{3} = \dfrac{ \: x + 1}{3}$

$\sf: \implies \: \dfrac{2x - 1}{ \not3} = \dfrac{ \: x + 1}{ \not3}$

$\sf :\implies \: 2x \: - \: \: 1 \: = \: x \: + \: 1$

$\sf : \implies \: 2x \: - \: x \: = \: 1 \: + \: 1$

$\sf : \implies \:\underline{\purple{ \bold{x = 2}}}$