(2x+1)×(3x+2) = 6 (x-1)(x-2)
Answers
Answered by
0
Step-by-step explanation:
(2x+1)*(3x+2)=6(x-1)*(x-2)
(6x^2+4x+3x+2)=6*(x^2-2x-x+2)
6x^2+7x+2=6x^2-18x+12
7x+2=-18x+12
25x=10
x=2/5
Similar questions