Question

(2x-1/3y) rage to the power 3

Answer 1

Answer :

Now,

${(2x - \frac{1}{3y} )}^{3} \\ \\ = {(2x)}^{3} - 3 {(2x)}^{2} ( \frac{1}{3y} ) + 3(2x) { (\frac{1}{3y}) }^{2} - {(3y)}^{3} \\ \\ = 8 {x}^{3} - \frac{ 4{x}^{2} }{y } + \frac{2x}{3y} - 27 {y}^{3}$

Formula :

${(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3}$

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Answer 2

Refer to the above attachment :)

BE BRAINLY!!