Question

if the equation x2-(2k+2)x+7k+1=0 has repeated real roots, find the value of k

Answer 1

Hey


The given equation is :-

x² - ( 2k + 2 ) x + 7k + 1 = 0


Now ,


it has equal roots .


So ,

D = 0


b² - 4ac = 0


( 2k + 2 ) ² - 4 * ( 7k + 1 ) = 0


=> 4k² + 4 + 8k - 28 k - 4 = 0


=> 4k² - 20k = 0


=> 4k ( k - 5 ) = 0


So ,

4k = 0

=> k = 0


And ,

k - 4 = 0

=> k = 4


thanks :)