Question

2x - 1
sec-'(x + b) = sec-x+ -
- 1
x - 1)3/2​

Answer 1

Answer:

secx+1

Explanation:

The numerator is a

difference of squares

and is factorised, in general, as shown.

here

a=secx and b=1

⇒sec2x 1=(secx−1)(secx+1 ⇒sec2x−1secx−1

=(secx−1)1(secx+1)secx−11 =secx+1