Question

How much calcium carbonate will be required to obtain
11.2 carbon di oxide
at NTP

​

Answer 1

Answer:

11.2L

Explanation:

Chemical reaction involved is:

CaCO

3

→CaO+CO

2

Molar mass of CaCO

3

=40+12+16×3=100 g

According to the balanced reaction 100 g of CaCO

3

produces 1 mol of CO

2

i.e. 22.4 L at STP.

∴50 g CaCO

3

will produce

100

22.4

×50=11.2 L CO

2

at STP.

Answer 2

The balanced equation is:

100g

1mol

CaCO

3

→CaO+

=22.4litreatNTP

1mol

CO

2

100g of CaCO

3

evolve carbon dioxide = 22.4 litre

20g CaCO

3

will evolve carbon dioxide

=

100

22.4

×=4.48litre