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∆H-∆E =nRT where n is mole difference between product and reactant only in gaseous state here mole means coefficient of molecule which present starting ,n=1-1/2 so n is 1/2 and putting the all value in equation then( -26.4)-∆E=1/2×0.002×298 after solving ∆ E = -26.7 kcal hope it may help you
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