2x+1÷x-1÷3=5÷24solve this
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This is how we solve this sum. Please ask me if u do not understand.
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sumu27:
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Hey mate!!
![\frac{2x + 1}{8} - \frac{x - 1}{3} = \frac{5}{24} \\ \\ \frac{3(2x + 1) - 8(x - 1)}{ \cancel{24}} = \frac{5}{ \cancel{24} } \\ \\ 6x + 3 - 8x + 8 = 5 \\ \\ 11 - 2x = 5 \\ \\ - 2x = 5 - 11 \\ \\ \cancel - \: 2x = \cancel - \: 6 \\ \\ 2x = 6 \\ \\ x = \frac{ \cancel6 {}^{ \: \: 3} }{ \cancel2} \\ \\ \bold{ \therefore \: x = 3} \frac{2x + 1}{8} - \frac{x - 1}{3} = \frac{5}{24} \\ \\ \frac{3(2x + 1) - 8(x - 1)}{ \cancel{24}} = \frac{5}{ \cancel{24} } \\ \\ 6x + 3 - 8x + 8 = 5 \\ \\ 11 - 2x = 5 \\ \\ - 2x = 5 - 11 \\ \\ \cancel - \: 2x = \cancel - \: 6 \\ \\ 2x = 6 \\ \\ x = \frac{ \cancel6 {}^{ \: \: 3} }{ \cancel2} \\ \\ \bold{ \therefore \: x = 3}](https://tex.z-dn.net/?f=+%5Cfrac%7B2x+%2B+1%7D%7B8%7D++-++%5Cfrac%7Bx+-+1%7D%7B3%7D+%3D++%5Cfrac%7B5%7D%7B24%7D+++%5C%5C++%5C%5C++%5Cfrac%7B3%282x+%2B+1%29+-+8%28x+-+1%29%7D%7B+%5Ccancel%7B24%7D%7D++%3D++%5Cfrac%7B5%7D%7B+%5Ccancel%7B24%7D+%7D+%5C%5C++%5C%5C+6x+%2B+3+-+8x+%2B+8+%3D+5+%5C%5C++%5C%5C+11+-+2x+%3D+5+%5C%5C++%5C%5C++-+2x+%3D+5+-+11+%5C%5C++%5C%5C+%5Ccancel+++-++%5C%3A+2x+%3D++%5Ccancel++-++%5C%3A+6+%5C%5C++%5C%5C+2x+%3D+6+%5C%5C++%5C%5C+x+%3D++%5Cfrac%7B+%5Ccancel6+%7B%7D%5E%7B++%5C%3A++%5C%3A+3%7D+%7D%7B+%5Ccancel2%7D++%5C%5C++%5C%5C++%5Cbold%7B+%5Ctherefore+%5C%3A+x+%3D+3%7D)
Thanks for the question!
Thanks for the question!
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