Question

The pH of lemon juice at 298K is 2.0.Calculate [ H3O+ ] & [ OH- ] in its solution. 

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Answer 1

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pH = -log [H3O+]

2.32 = -log [H3O+]

antilog (- 2.32) = [H3O+]

[H3O+] = 4.786 x 10^-3

[OH-] = 10^-14 / 4.786 x 10^-3 = 2.09 x 10-1^2

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BTS AND EXO

Answer 2

Answer:

I have don't know math

Explanation:

soort