Question

(2x+1) (x-1) Please solve it,s really urgent. Find value of x as zero polynomial . ​

Answer 1

Answer:

x=-$\frac{1}{2}$,1

Step-by-step explanation:

P(x)=(2x+1)(x-1)=0

⇒(2x+1)(x-1)=0

⇒2x+1=0 , x-1=0

⇒x=$-\frac{1}{2}$,1

More about solving the zeros of any Quadratic Equation:-

The Quadratic Formula:

Given a quadratic equation in the following form:

ax² + bx + c = 0

...where a, b, and c are the numerical coefficients of the terms of the quadratic, the value of the variable x is given by the following equation:

$x=\frac{-b±\sqrt{b^2-4ac} }{2a}$