Question

Please solve this question ... ​

Answer 1

In the given figure , the following information is given -

AB is parallel to CD and ED Is the transversal , cutting at G and H respectively .

Angle EGB = 35°

QP is perpendicular to EF .

To find -

Find the measure of angle PQH

Solution -

Let us assume that the measure of angle PQH is x° .

Now , Angle EGB and angle EHD are corresponding angles.

Hence ,

Angle EGB = Angle EHD = 35°

Now , Angle QHP and Angle EHD are vertically opposite angles .

So , Angle QHP = 35°

Now , we know that the sum if all angles in a triangle is 180°

Consider ∆ QHP

Angle QHP + Angle QPH + Angle PQH = 180°

=> 35° + 90° + x = 180°

=> x + 125° = 180°

=> x = 55°

This , the required measure of angle PQH is 55°

This is the answer .

_______

Answer 2

Answer:

Hello ! mates here's Ur ans.....

Given;

AB || CD.

<EGB= 35°.

PQ |_ EF

Solution:

<EGB = EHD = 35° ( corresponding angles)..

and, < EHD = <CHF = 35° ( vertically opposite angles)..

now, in ∆ QPH ;

90+35+X = 180°

= 125 + X = 180

= X= 180-125=55°(ANS)..

HOPE! ITS HELPFUL...

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