Math, asked by mugdha10, 11 months ago

2x-10/x=1 solve by factorization method

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Answered by sivaprasath

Answer:

The factors are (2x - 5) & (x + 2).

Hence,

$x = \frac{5}{2}$ or $x = -2$

Step-by-step explanation:

Given :

To factorize,

$2x - \frac{10}{x} = 1$

Solution :

$2x - \frac{10}{x} = 1$

⇒ $\frac{2x^2 - 10}{x} = 1$

⇒ $2x^2 - 10 = x$

⇒ $2x^2 - x - 10 = 0$

⇒ $2x^2 + 4x - 5x - 10 = 0$

⇒ $2x(x + 2) - 5(x + 2) = 0$

⇒ $(2x - 5)(x + 2) = 0$

∴ The factors are (2x - 5) & (x + 2).

Hence,

$x = \frac{5}{2}$ or $x = -2$

azit89mukhia: 2x - 10/x = 1
Or, □((2〖x 〗^(2 )- 10)/x) = 1
Or, 2〖x 〗^(2 )– 10 = x
Or, 2〖x 〗^(2 )- x- 10= 0
0r, 2〖x 〗^(2 )–(5-4)x- 10 = 0
Or, 2〖x 〗^(2 )- 5x+4x- 10 = 0
Or, x(2x – 5) + 2(2x – 5)= 0
∴ (2x – 5) (x + 2) = 0
Either, (2x – 5) = 0 0r, (x + 2)= 0
Or, 2x = 5 ∴ x = -2
∴ x=5/2

sivaprasath: I thought they asked factors , not zeroes,.

azit89mukhia: ya ...we wll get two factors

sivaprasath: yeah , zeroes means values of x, and factors means products

azit89mukhia: ur correct

Answered by gdkedar1972

Answer:

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2x-10/x=1 solve by factorization method