2x^2-2√2x+1=0 factorize,step-by-step with full method
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2
Answer:
2x² - 2√2x + 1 = 0
2x² - √2x - √2x + 1 = 0
√2x ( √2x - 1 ) - 1 ( √2x - 1 ) = 0
( √2x - 1 ) ( √2x - 1 ) = 0
* ( √2x - 1 ) = 0
x = 1/√2
* ( √2x - 1 ) = 0
x = 1/√2
Answered by
1
Answer:
Simplify —
2
Equation at the end of step
1
:
1
((2 • (x2)) - 2x) + — = 0
2
STEP
2
:
Equation at the end of step
2
:
1
(2x2 - 2x) + — = 0
2
STEP
3
:
Rewriting the whole as an Equivalent Fraction
3.1 Adding a fraction to a whole
Rewrite the whole as a fraction using 2 as the denominator :
Step-by-step explanation:
hope it will clear to you
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