Question

2x^2+(2x+2)^2=340 solve this​

Answer 1

Step-by-step explanation:

$2 {x}^{2} + (2x + 2) ^{2} = 340 \\ \\ 2 {x}^{2} + 4 {x}^{2} + 4 + 8x = 340 \\ \\ 6 {x}^{2} + 8x - 336 = 0 \\ \\ 3 {x}^{2} + 4x - 168 = 0$

$x = \frac{ - b + \sqrt{ {b}^{2} - 4 \times a \times c} }{2 \times a}$

and

$x = \frac{ - b - \sqrt{ {b}^{2} - 4 \times a \times c} }{2 \times a}$

$x = \frac{ - 4 + \sqrt{ { ( - 4)}^{2} - 4 \times 3 \times ( - 168)} }{2 \times 3}$

and

$x = \frac{ - 4 - \sqrt{ { ( - 4)}^{2} - 4 \times 3 \times ( - 168)} }{2 \times 3}$

.:

$x = 6.8$

and

$x = - 8.1$

Answer 2

Answer:

Step-by-step explanation:

2x^2+(2x+2)^2=340

2x^2 + 4x^2 + 4 + 8x = 340

6x^2 + 8x + 4 = 340

3x^2 + 4x + 2 = 170

3x^2 + 4x - 168 = 0

NOW FURTHER YOU MAY SOLVE IT...

Hope it helps :)