Math, asked by hermionegranger1711, 4 months ago

2x^2+(2x+2)^2=340 solve this​

Answers

Answered by ab548
2

Step-by-step explanation:

2 {x}^{2}  + (2x + 2) ^{2}  = 340 \\  \\ 2 {x}^{2} + 4 {x}^{2}  + 4 + 8x = 340 \\  \\ 6 {x}^{2}  + 8x - 336 = 0 \\  \\ 3 {x}^{2}  + 4x - 168 = 0

x =  \frac{ - b +  \sqrt{ {b}^{2}  - 4 \times a \times c} }{2 \times a}

and

x =  \frac{ - b  -  \sqrt{ {b}^{2}  - 4 \times a \times c} }{2 \times a}

x =  \frac{ - 4 +  \sqrt{ { ( - 4)}^{2}  - 4 \times 3 \times ( - 168)} }{2 \times 3}

and

x =  \frac{ - 4  -   \sqrt{ { ( - 4)}^{2}  - 4 \times 3 \times ( - 168)} }{2 \times 3}

.:

x =  6.8

and

x =  - 8.1

Answered by dhrugupt
3

Answer:

Step-by-step explanation:

2x^2+(2x+2)^2=340

2x^2 + 4x^2 + 4 + 8x = 340

6x^2 + 8x + 4 = 340

3x^2 + 4x + 2 = 170

3x^2 + 4x - 168 = 0

NOW FURTHER YOU MAY SOLVE IT...

Hope it helps :)

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