Question

2x^2 - 32x + 128


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Answer 1

Answer: 2x^2 - 32x + 128 = 0

2(x^2 - 16x + 64) = 0

x^2 - 16x + 64 = 0

x^2 - 8x - 8x + 64 = 0

x(x - 8) - 8(x - 8) = 0

(x - 8) (x - 8) = 0

x = 8

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