Question

√2x^2 - 3x - 2√2 = 0 by completing square​

Answer 1

Answer:

Divide it by √2

x² - 3x/√2 - 2 = 0

x² - 3x/√2 = 2

x² - 3x/√2 + (3/√2 * 1/2)² = 2

x² - 3x/√2 + (3/2√2)² = 2 + (2√2)²

(x - 3/2√2)² = 2 + 9/4 * 2

(x - 3/2√2)² = 16 + 9/8

(x - 3/2√2)² = 25/8

x - 3/2√2 = ±√25/√8

x - 3/2√2 = ±5/2√2

x - 3/2√2 = 5/2√2        and    x - 3/2√2 = - 5/2√2

x = 5/2√2 + 3/2√2                 x = -5/2√2 + 3/2√2

x = 8/2√2                               x = -2/2√2

x = √8                                     x = -1/√2