Question

2x^2+3y^2=35 and x^/2+y^2/3=5 Find x and y​

Answer 1

Answer:

Step-by-step explanation:

Given that

2x^2 + 3y^2 =35 and x^2/2 + y^2/3 =5

So taking this equation

x^2/2 + y^2/3 =5

3x^2 +2y^2 = 30

2x^2 + 3y^2 =35 (×3)

3x^2 + 2y^2 = 30 (×2)

It becomes as

6x^2 + 9y^2 =105

6x^2 + 4y^2 = 60

Solving both we gets as this ...

5y^2 = 45

y^2 = 9

answer of y = 3

Now take this equation

6x^2 + 4y^2 =60

6x^2 +4×3×3=60

6x^2 = 60-36

6x^2 =24

x^2=4

Answer of x=2