Question

(2x^2-3y^2-4) (3x^2-y^2+7) find the product​

Answer 1

Answer:

6x⁴+3y⁴-11x²y²+2x²-17y²-28

Step-by-step explanation:

see the above pic

Answer 2

$(2 {x}^{2} - 3 {y}^{2} - 4)(3 {x}^{2} - {y}^{2} + 7) \\ =( {6x}^{4} - 2 {x}^{2} {y}^{2} + 14 {x}^{2} - 9 {x}^{2} {y}^{2} + 3 {y}^{4} - 21 {y}^{2} - 12 {x}^{2} + 4 {y}^{2} - 28) \\ 6 {x}^{4} +3 {y}^{4} + 2 {x}^{2} - 17 {y}^{2} - 11 {x}^{2} {y}^{2} - 28$