2x^2+5/3x-2=0 in square method
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Hey
Multiply the whole equation by 3
we get 6x² +5x - 6 = 0
6x² +9x - 4x -6 =0
3x(2x + 3) - 2(2x + 3) = 0
(3x-2)=0 or (2x+3)=0
x = 2/3 or x = -3/2
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Answered by
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Given 3x
2
−5x+2=0
Here, the coefficient of x
2
is 3 and it is not a perfect square.
∴ Multiply the equation throughout by 3.
⇒(3x
2
−5x+2=0)×3∴9x
2
−15x+6=0
Now, half of the coefficient of x is
25
.∴b= 25and b 2 =( 25 ) 2
So, 9x2 −15x+( 25 )
2 −( 25 ) 2
+6=0,(3x) 2
−15x+( 25 )
2 =( 25 ) 2
6=0,(3x) 2
−15x+( 25 )
2 =( 25 ) 2
−6(3x− 25 )
2 = 425
−6= 41
(Taking square root on both the sides)
3x− 25
=± 21
∴3x− 25
=± 21 or 3x− 25
=− 21
3x= 21 + 25
3x= 25 − 21
3x= 26 =3
3x= 24 =2
∴x=1 x= 32
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