2x^2 + 52x = 8 find x
Very urgent pls tell answer
Answers
Answered by
0
Step-by-step explanation:
2X^2+52X=8
=> 2X^2+52X-8=0
=> X^2+26X-4=0
=> X`= [-26+√{(26)^2+(4×1×4)}]/2
=>0.15
OR, X=[-26-√{(26)^2+16}]/2
=> X=-26.16
Answered by
1
Step-by-step explanation:
2x^2+52x=8
x^2+26x = 4
x^+ 26x - 4=0
x^2+2(13)(x) +(13)^2-(13)^2-4=0
(x +13)^2 -169-4=0
(x+13)^2 -173 =0
(x+13)^2 -(√173)^2=0
(x+13+√173)(x+13-√173)=0
if
x+13+√173=0
x=-13-√173
if
x+13-√173=0
x=√173-13
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