Math, asked by shambhavim15, 1 year ago

2x^2 + 52x = 8 find x

Very urgent pls tell answer

Answers

Answered by Diptanshu11
0

Step-by-step explanation:

2X^2+52X=8

=> 2X^2+52X-8=0

=> X^2+26X-4=0

=> X`= [-26+{(26)^2+(4×1×4)}]/2

=>0.15

OR, X=[-26-{(26)^2+16}]/2

=> X=-26.16

Answered by rishu6845
1

Step-by-step explanation:

2x^2+52x=8

x^2+26x = 4

x^+ 26x - 4=0

x^2+2(13)(x) +(13)^2-(13)^2-4=0

(x +13)^2 -169-4=0

(x+13)^2 -173 =0

(x+13)^2 -(√173)^2=0

(x+13+√173)(x+13-√173)=0

if

x+13+√173=0

x=-13-√173

if

x+13-√173=0

x=√173-13

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