Question

2x^2-5x+3 =0 solve completimg square method ​

Answer 1

Answer:

$2 {x}^{2} - 3x - 2x + 3 = 0 \\ \\ \\ = > x(2x - 3) - 1(2x - 3) = 0 \\ \\ \\ = > x = 1 \\ 2x - 3 = 0 \\ \\ = > x = \frac{3}{2}$

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Answer 2

$refer \: to \: attachment$

hey mate here is your answer

2x^2-5x+3=0

Divide each term with 2

x^2-5/2*x+3/2=0

x^2 -2*x*5/4+(5/4)^2-(5/4)^2+3/2=0

(x-5/4)^2=(5/4)^2-3/2

(x-5/4)^2= 25/16-3/2

=(25-24)/16

=1/16

Therefore

(x-5/4)= 1/4 or x-5/4=-1/4

x=1/4+5/4 or x=-1/4+5/4

x=6/4 or x=4/4

x=-3/2 1

COMPLETING SQUARE