Question

2x^2-5x-3=0 solve the following quadratic equation.​

Answer 1

Answer:

x=3 or -1/2

Step-by-step explanation:

2x^2 -5x -3 =0

2x^2 -6x +x -3 =0 (splitting the middle term)

2x (x-3) +1 (x-3)=0 (taking common)

(2x+1)(x-3) =0

Applying zero product rule,

we get,

either 2x+1 = 0

2x=-1

x=-1/2

or x-3=0

x=3

hope you understood awaiting your reply and support.

Answer 2

Answer:

2x^2-5x-3=0

2x^2-6x+x-3=0

2x(x-3)+1(x-3)=0

(x-3)(2x+1)=0

x-3=0

x=3

2x+1=0

2x= -1

x= -1/2

x=3, -1/2