Question

2x^2-5x+3 completing the squares method....fast its urgent

Answer 1

2x^2-5x+3=0
Divide each term with 2
x^2-5/2*x+3/2=0

x^2 -2*x*5/4+(5/4)^2-(5/4)^2+3/2=0
(x-5/4)^2=(5/4)^2-3/2
(x-5/4)^2= 25/16-3/2

=(25-24)/16
=1/16
Therefore
(x-5/4)= 1/4 or x-5/4=-1/4
x=1/4+5/4 or x=-1/4+5/4
x=6/4 or x=4/4
x=-3/2 or x=1