2x^2-5x+3 completing the squares method....fast its urgent
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2x^2-5x+3=0
Divide each term with 2
x^2-5/2*x+3/2=0
x^2 -2*x*5/4+(5/4)^2-(5/4)^2+3/2=0
(x-5/4)^2=(5/4)^2-3/2
(x-5/4)^2= 25/16-3/2
=(25-24)/16
=1/16
Therefore
(x-5/4)= 1/4 or x-5/4=-1/4
x=1/4+5/4 or x=-1/4+5/4
x=6/4 or x=4/4
x=-3/2 or x=1
Divide each term with 2
x^2-5/2*x+3/2=0
x^2 -2*x*5/4+(5/4)^2-(5/4)^2+3/2=0
(x-5/4)^2=(5/4)^2-3/2
(x-5/4)^2= 25/16-3/2
=(25-24)/16
=1/16
Therefore
(x-5/4)= 1/4 or x-5/4=-1/4
x=1/4+5/4 or x=-1/4+5/4
x=6/4 or x=4/4
x=-3/2 or x=1
mysticd:
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