-2x^2-6x-18 find the zeroes
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This question can be solved using quadratic formula only
1Harsh111:
you can explain the answer
see the other ans
if u want an explanation
the ans is right or wrong
it's wrong
u hv not taken -2 common from -6x
i taken u can check
Answered by
1
-3 and -3
-2x2-6x-18
(-2) take as common
-2 (x2+3x+9)
x2+3x+9=0
x2+3x+3x+9=0(x+3) (x+3)
-2x2-6x-18
(-2) take as common
-2 (x2+3x+9)
x2+3x+9=0
x2+3x+3x+9=0(x+3) (x+3)
it's right
thnx
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