Question

From the adjoining figure find

Answer 1

Sum of angles in a quadrilateral = 360°

(i)

angle CBA =( 50 + x )°

(3x + 10)° + (5x + 8) + (50 + x)° + (3x + 4)° = 360°

3x° + 10° + 5x° + 8° + 50° + x° + 3x° + 4° = 360°

12x° + 72° = 360°

12x° = 360° - 72°

12x° = 288°

x = 288/12°

x = 24°


(ii)

angle DAB = 3x + 4 °

= 3(24) + 4

= 72 + 4 = 76°


(iii)

angle ADB = 3x + 10°

= 3(24) + 10°

= 72° + 10°

= 82°

Answer 2

Answer

(i) x = 24°

(ii) /_ DAB = 76°

(iii) /_ ADB = 82°

Step-by-step explanation:

Here is your solution

CBA = ( 50 + x )°

( 3x + 10 )° + ( 5x + 8 )° + ( 50 + x )° + ( 3x + 4 )° = 360°

( 3x + 5x + x + 3x + 10 + 8 + 50 + 4 )° = 360°

12x° + 72° = 360°

solution is given in picture

I Hope It Helps You