Question

2x^2-6x+3=0
${2x}^{2} - 6x + 3 = 0$
find the nature of roots of the following quadratic equation​

Answer 1

We could find the nature of roots by finding Discriminant

By using the Formula

b^2-4ac

(-6)^2-4×2×3

36-24

12>0

Therefore 12>0 then the given quadratic eq. have distinct real roots

Sorry but ur question was incomplete(2x^2-6x(+-)3??? I gave the +value

Answer 2

HEYA!

Your Answer is in the attachment. Please refer to it.

The discriminant formula ( b² - 4ac ) is used .

CONDITIONS-

•If discriminant > zero , then it has real and unequal roots.

•If discriminant = zero , then it has real and equal roots.

•If discriminant < zero , then it has unreal roots.

Note- You forgot to give the sign of c i.e. 3 .So I supposed it to be +ve.

Hope this Helps!