Question

2x^2-7x+3=0 find completing the square

Answer 1

2x2-7x+3=0

x2-7x/2+3/2=0

x2-2*7x/4+3/2=0

x2-2*7x/4+49/16=(49/16)-(3/2)

(x-7/4)2=25/16

x-7/4=+5/4

or

x-7/4=-5/4

so

x=3 or 1/2

Hope it helped......

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

2x² - 7x + 3 = 0

$\implies{x^{2}-\dfrac{7}{2}x +\dfrac{3}{2}=0$

$\implies{x^{2}-\dfrac{7}{2}x = -\dfrac{3}{2}=0$

$\implies{x^{2}-\dfrac{7}{2}x +(\dfrac{7}{4})^{2}$

$\implies{(\dfrac{7}{4})^{2} -\dfrac{3}{2}$

$\implies{(x-\dfrac{7}{2})^{2}=\dfrac{49-24}{16}$

$\implies{(x-\dfrac{7}{4})^{2}=\dfrac{25}{16}$

$\implies{x-\dfrac{7}{4}=\pm\dfrac{5}{4}$

$\implies{x=\dfrac{7}{4}\pm\dfrac{5}{4}$

$\implies{x=3\;or\;\dfrac{1}{2}$

$\textbf{\boxed{Roots\;of\;Equation}}$

$\implies{x=3\;and\;\dfrac{1}{2}$

$\boxed{\begin{minipage}{11 cm} Additional Information \\ \\ \;There\;are\;3\; methods\;to\;find\;roots\;of\; Quadratic\; Equation \\ \\ 1.By\; Factorisation \\ \\ 2.By\; Completing\;Squares \\ \\ 3.By\;the\;use\;of\;Quadratic\;Formula \end{minipage}}$