Question

2x^2-7x-39 factorise

Answer 1

2x^2-13x+6x-39
x(2x-13) 3(2x-13)
(2x-13)(x+3)
I hope you get this answer.

Answer 2

$\sf\blue{\underline{\underline{\: \: Answer : \: }}}$

2x² - 7x - 39

The Given Expression is 2x² - 7x - 39

Here,

2 × (-39) = -78

So,

We try to split -7 into two parts whose sum is -7 and product -78.

clearly, (-13) + 6 = -7 and (-13) × 6 = -78

$\implies\sf{2x^2 - 7x - 39} \\ \implies\sf{2x^2 - 13x + 6x - 39} \\ \implies\sf{x(2x - 13) + 3(2x - 13)} \\ \implies\sf{ (2x-13) (x+3)}$

Hence,

$\sf\pink{ (2x-13) (x+3)}$ is the Factors.