2x^2-7x+6=0
Solve it please
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2x^2-7x+6=0
2x^2-4x-3x+6=0
2x(x-2)-3(x-2)=0
(x-2) (2x-3)
Hope it helpful
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2x² - 7x + 6 = 0
2x² -4x -3x + 6 = 0
2x (x -2) -3 ( x -2) = 0
(2x -3) (x-2) = 0
2x -3 =0 or x - 2= 0
x = 3/2 or x = 2.
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