Question

2x^2+8x-k^3=0 FIND THE VALUE OF K​

Answer 1

Answer:

=> k = + 2 √2

Step-by-step explanation:

roots of a quadratic equation given by

x = -b + √ ( b^2-4ac) / 2a { quadratic formula }

if this has equal roots then discriminent D must equal to 0

so that , x = -b + 0 / 2a = -b/2a

here b = 8

a = 2

c = k^3

=> (8) ^2 - 4×2 ×k^3 = 0

=> 8( 8 - k^3 ) = 0

=> k^3 = 8

=> k = + (8)^ 1/3

=> k = + 2 √2