Question

2x^2-9=0 solve using factorisation method i am urgently in need of this

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

$x \: = > \frac{ \sqrt{72} }{4}$

$x = > \: - \: ( \frac{ \sqrt{72} }{4} )$

Step-by-step explanation:

Explosion:-

$\huge{\underline{\underline{\mathbb{\red{Given:-}}}}}$

$2 {x}^{2} - \: 9 = 0$

Quadratic equation normally look like this

$a {x}^{2} + \: bx \: + \: c \: = 0$

In the given equation the bx team is missing we shall supply it

${2}^{x} + 0 - 9$

Then as per formula the roots are

$x = \frac{ - b = \sqrt{b2 - 4ac} }{2a}$

We shell substitute the values in the formula

$x = \frac{( - 0) = \sqrt{ {0}^{2} - (4 \times 2 \times (9))} }{2a}$

we shall substitute the values in the formula

$x = \frac{ = \sqrt{0 - ( - 72} }{4}$