Question

2x^2 cos60 degree - 4cot^2 45 degree - 2tan60 degree =0 then find value of x

Answer 1

Step-by-step explanation:

I think this is the answer

I think it is correct

Answer 2

Answer:

2x^2 cos 60° -4 cot^2 45°-2 tan 60°=0

= 2x^2 × 1/2 -4 ×(1) 2 - 2 × root3 =0

=x2 -4 -2 root3 =0

=x2 = 4+2root3

=x2 =3 +1+ 2 root3 =x2 = ( root3)2 + (1)2 + 2root3

=x2 = ( root3 +1)2

= x = root3 +1.