Math, asked by PAVANROHITH2418, 9 months ago

(2x)^2-x+1/8 solve by factorisation method

Answers

Answered by ARJUN031105
1

Answer: 2x^2×8-x×8+1/8×8

16x^2-8x+1

16x^2-4x-4x+1

4x(4x-1) -1(4x-1)

(4x-1) (4x-1)

Hope it help you

Please mark me brainliest

Similar questions