2x^2+x+5 prove no real roots
Answers
Answered by
9
Solution :
For no real roots D must be < 0
= D = b^2 - 4ac
= 1^2 4*2*5
= 1 - 40
= -39 < 0
so, it have no real roots.
_____________
Hope it helps
#Amrit⭐
For no real roots D must be < 0
= D = b^2 - 4ac
= 1^2 4*2*5
= 1 - 40
= -39 < 0
so, it have no real roots.
_____________
Hope it helps
#Amrit⭐
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Answered by
1
Hey friend, ☺ here is ur answer ___________________________
Condition for no real roots :- D < 0
D = b^2 - 4ac, where a = 2 , b = 1 and c = 5
D = (1)^2 - 4 × 2 × 5 = 1 - 40 = -39
-39 < 0
this proves that 2x^2 + x + 5 has no real roots.
hope this helps u..
Condition for no real roots :- D < 0
D = b^2 - 4ac, where a = 2 , b = 1 and c = 5
D = (1)^2 - 4 × 2 × 5 = 1 - 40 = -39
-39 < 0
this proves that 2x^2 + x + 5 has no real roots.
hope this helps u..
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