Question

2x/3+1=7x/15+3

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Answer 1

Question:

$\frac{2x}{3}+1=\frac{7x}{15}+3$,To Find value of x

Given:

$\frac{2x}{3}+1=\frac{7x}{15}+3$

To Find:

The value of x

Solution:

$\frac{2x}{3}+1=\frac{7x}{15}+3$

Solving the first part:

$\frac{2x}{3}+1$

Lcm=3

$\frac{2x+1\times3}{3}$

$\frac{2x +3}{3}$

Solving part second part :

$\frac{7x}{15}+3$

Lcm=15

$\frac{7x}{15}+3\times\frac{15}{15}$

$\frac{7x +45}{15}$

Taking both:

$\frac{2x+3}{3}=\frac{7x+45}{15}$

Now on doing cross multiplication we get,

15(2x+3)=3(7x+45)

30x+45=21x+135  

On solving this we get,

9x=90  

x=10  

Therefore, the value of x after solving the equation $\frac{2x}{3}+1=\frac{7x}{15}+3$ is 10  

Answer:

The value of x after solving the equation $\frac{2x}{3}+1=\frac{7x}{15}+3$ is 10  

Answer 2

Answer:

Step-by-step explanation:

Given = 2x/3+1=7x/15+3

Multiplying both sides by the LCM of 3 and 15

15(2x/3+1) =  15(7x/15+3)

10x+15=7x+45

⇒10x−7x=45−15  

[Transposing 7x to LHS and15 to RHS]

⇒3x=30

⇒x=10

Clearly, LHS = RHS

hope it helps