(2x+3)^2=25 solve the quadratic equation
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(2x+3)^2 = 25
(2x)^2 + 2 (2x) (3) + (3)^2. = 25. ( since (a+b)^2 = a^2 + 2ab + b^2 )
4x + 12x + 9 = 25
16x + 9 = 25
16x = 25 - 9
16x = 16
X = 16 / 16
X = 1
ruchitolambiya:
Hey how did u do that
why is there any wrong
The identity u use was correct but it is 4x^2
Coz there is square in the identity
you are also right but in this way it reacts like 4x
Ooo. But when I'm trying to solve it is not solving due to the square
ohh
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