Question

( 2x-3) (2x-3) + (x+4)^2​

Answer 1

${\mathbb{\huge{HOLA!!}}}$

(2x-3)×(2x-3)+(x+4)²

=(2x-3)²+(x+4)²

=[(2x)²+(4)²-2(2x×3)]+[(x)²+(4)²+2(x×4)]

=[4x²+16-2(6x)]+[x²+16+8x]

=4x²+16-12x+x²+16-8x

=4x²+x²+16+16-12x-8x

=5x²-20x+32

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