Question

(2x+3)^3+64 factorize

Answer 1

hope so now u can factorise

Answer 2

Answer:

Step-by-step explanation:

(2x+3)^3+64

=(2x)^3 + 3^3 + 3*2x*2x*3 + 3*2x*3*3. [(a+b)^3= a^3 + b^3 + 3*a*a*b + 3*a*b*b]

=8x^3 + 27 + 36x^2 + 54x

=8x^3 + 36x^2 + 54x + 27

Done