2x-3/3x-1=2x+3/3x+4
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Answered by
0
(2x-3)/(3x-1)=(2x+3)/(3x+4)
by transposing,
(2x-3)(3x+4)=(2x+3)(3x-1)
6x²+8x-9x-12=6x²-2x+9x-3
6x²-x-12=6x²+7x-3
6x²-x-12-6x²-7x+3=0
-8x-9=0
by taking (-) common,
-(8x+9)=0
8x+9=0
8x=-9
x=-9/8
by transposing,
(2x-3)(3x+4)=(2x+3)(3x-1)
6x²+8x-9x-12=6x²-2x+9x-3
6x²-x-12=6x²+7x-3
6x²-x-12-6x²-7x+3=0
-8x-9=0
by taking (-) common,
-(8x+9)=0
8x+9=0
8x=-9
x=-9/8
Answered by
0
(2x-3)(3x+4)=(2x+3)(3x-1)
=6x^2+8x-9x-12=6x^2-2x+9x-3
=8x-2x=18x+9
=12x=-9
=x=-9/12
=x=-3/4
=6x^2+8x-9x-12=6x^2-2x+9x-3
=8x-2x=18x+9
=12x=-9
=x=-9/12
=x=-3/4
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