Math, asked by anubhav35, 1 year ago

prove that
$cos6x = 32cos ^{6}x - 48 {cos}^{4}x + 18 {cos}^{2}x - 1$

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Answered by anuj99999999

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Answered by sandy1816

$\large \: cos6x \\ \\ = cos3.2x \\ \\ = 4 {cos}^{3} 2x - 3cos2x \\ \\ = 4(2 {cos}^{2} x - 1) ^{3} - 3(2 {cos}^{2} x - 1) \\ \\ = 4(8 {cos}^{6} x - 12 {cos}^{4} x + 6 {cos}^{2} x - 1) - (6 {cos}^{2} x - 3) \\ \\ = 32 {cos}^{6} x - 48 {cos}^{4} x + 24 {cos}^{2} x - 4 - 6 {cos}^{2} x + 3 \\ \\ = 32 {cos}^{6} x - 48 {cos}^{4} x + 18 {cos}^{2} x - 1$

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