Math, asked by kajal192, 1 year ago

prove that 1/secx-tanx -1/cosx =1/cosx-1/secx+tanx

bushivennavelly: can we go....formula method for any polynomial sum...
like finding roots....can we do??
in word problems.....other than factorization
for class 10

bushivennavelly: dont know y i cant ask a question....frm my acct

bushivennavelly: tell some1

Answers

Answered by deepak530

hope it is helpful for you

Attachments:

bushivennavelly: wt a great paper....u wrote

bushivennavelly: cant understand

kajal192: thanks

deepak530: why

deepak530: welcome

deepak530: please do comment on question good ways

Answered by mysticd

Hi ,

LHS = 1/( secx - tanx ) - 1/cos x

= (secx + tanx )/[(secx-tanx)(secx+tanx) -1/cosx

= ( secx + tanx ) / ( sec²x - tan² x ) - secx

[ since sec² x - tan² x = 1 ]

= secx + tanx - secx

= tanx ----( 1 )

RHS = 1/cosx - 1/ ( secx + tanx )

= secx - (secx - tanx ) / [(secx + tanx)(secx-tanx)

= secx - ( secx - tanx ) / ( sec² x - tan² x )

= secx - secx + tanx

= tanx ---( 2 )

from ( 1 ) and ( 2 ) ,

LHS = RHS

I hope this helps you.

: )

kajal192: h par complicated h thoda sa

kajal192: par acha h

bushivennavelly: grt

Previous Question

Next Question