Question

(2x + 3) (3x - 4) = 6x² + 8x + a
find the value of a.
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Answer 1

Answer:

(2x+3)(3x-4)=6x^2+8x+a

6x^2-8x+9x-12=6x^2+8x+a

6x^2-6x^2-8x-8x+9x-12=a

a=-7x-12

THEREFORE value of a=-7x-12

Answer 2

$2x + 3 + 3x - 4 = 6 {x }^{2} + 8x + a$

$5x - 1 = 6 {x}^{2} + 8x + a \\ 5x - 8x - 1 = 6 {x}^{2} + a \\ - 3x - 1 = 6 {x}^{2} + a \\ - 3x - 1 = 6 {x}^{2} + a \\ (- 3x - 1 )\times 6 = {x}^{2} + a \\ - 18x - 6 = {x}^{2} + a$