Math, asked by amitsri0702, 4 months ago

(2x+3)-(5x-7)/6x+1=-8/3
please answer my question I will mark as brainiest​

Answers

Answered by IntrovertLeo
5

Given:

\dfrac{(2x+3)-(5x-7)}{6x+1}=\dfrac{-8}{3}

What to find?

We have to find the value of x.

Solution:

\dfrac{(2x+3)-(5x-7)}{6x+1}=\dfrac{-8}{3}

Solve the brackets in the numerator in LHS,

\dfrac{2x+3-5x+7}{6x+1}=\dfrac{-8}{3}

Using cross multiplication,

⇒ 3(2x + 3 - 5x + 7) = -8(6x + 1)

Remove the brackets,

⇒ 6x + 9 - 15x + 35 = -48x - 8

Rearrange the terms,

⇒ 6x - 15x + 9 + 35 = -48x - 8

Solve the terms,

⇒ -9x + 44 = -48x - 8

Take the constant and variable to LHS and RHS respectively,

⇒ -9x + 48x = -8 - 44

Solve the LHS and RHS,

⇒ 39x = -52

Take 39 to RHS,

⇒ x = \dfrac{-52}{39}

So the value of x is \dfrac{-52}{39}.

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