Question

2x^3-8x^2-64x=0.........find the value of x//////////​

Answer 1

Answer:

x=8,-4

Step-by-step explanation:

2x³-8x²-64x=0

2x³-8x²=64x

2x²(x-4)=64x

x-4=64x/2x²

=32/x

x-4=32/x

x²-4x=32

x²-4x-32=0

(ab= -32 and a+b= -4

a= -8 and b=4)

x²-8x+4x-32=0

x(x-8)+4(x-8)=0

(x+4)(x-8)=0

x=8,-4