Question

2x -3 by 4 x + 5 = 1 by 3​

Answer 1

Required Answer:-

Given:

• $\sf \dfrac{2x - 3}{4x + 5} = \dfrac{1}{3}$

To find:

• The value of x.

Solution:

We have,

$\sf \implies \dfrac{2x - 3}{4x + 5} = \dfrac{1}{3}$

On cross multiplying, we get,

$\sf \implies 3(2x - 3) = 4x + 5$

$\sf \implies 6x - 9 = 4x + 5$

$\sf \implies 6x - 4x = 9+ 5$

$\sf \implies 2x = 14$

$\sf \implies x = 7$

★ Hence, the value of x is 7.

Answer:

• The value of x is 7.

Verification:

Let us verify our result.

Taking LHS,

$\sf\dfrac{2x - 3}{4x + 5}$

$\sf = \dfrac{14 - 3}{28 + 5}$

$\sf = \dfrac{11}{33}$

$\sf = \dfrac{1}{3}$

= RHS

Therefore, LHS = RHS

Hence, the value of x is 7 (Verified ✔)

Answer 2

Answer:

$\sf{x=7}$

Step-by-step explanation:

$\sf{\displaystyle\frac{2x-3}{4x+5}=\frac{1}{3}}$

• Cross Multiply

$\to\sf{\left(2x-3\right)\cdot \:3=\left(4x+5\right)\cdot \:1}$

$\to\sf{\left(2x-3\right)\cdot \:3=\left(4x+5\right)}$

$\to\sf{6x-9=4x+5}$

• Add 9 to Both Sides

$\to\sf{6x-9+9=4x+5+9}$

$\to\sf{6x=4x+14}$

• Subtract 4x from Both Sides

$\to\sf{6x-4x=4x+14-4x}$

$\to\sf{2x=14}$

• Dividing both Sides by 2

$\to\sf{x=7}$